C=0.1x^2-20x+1200

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Solution for C=0.1x^2-20x+1200 equation: 



=0.1C^2-20C+1200

We move all terms to the left:

-(0.1C^2-20C+1200)=0

We get rid of parentheses

-0.1C^2+20C-1200=0

a = -0.1; b = 20; c = -1200;
Δ = b2-4ac
Δ = 202-4·(-0.1)·(-1200)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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